A (blindfolded) marksman finds that on the average he hits the target 4 times out of 5. If he fires 4 shots, what

is the probability of :

(a) more than 2 hits?

(b) at least 3 misses?

Using the binomial distribution, it is found that there is a:

a) 0.9728 = 97.28% probability of more than 2 hits.

b) 0.0272 = 2.72% probability of at least 3 misses.

For each shot, there are only two possible outcomes, either he hits the target, or he does not. The probability of hitting the target on a shot is independent of any other shot, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

The parameters are:

In this problem:

Item a:

This probability is:

Then:

0.9728 = 97.28% probability of more than 2 hits.

Item b:

At least 3 misses is less than 2 hits, hence:

0.0272 = 2.72% probability of at least 3 misses.

To learn more about the binomial distribution, you can take a look at link

answer set (b) 0.5, 3/4 80% is in order from least to greatest.  

step-by-step explanation:

in order to compare rational numbers to each other, it is much easier if they are in the same form.   typically, the best form in which to evaluate rational numbers is in decimals.   in order to convert a percent to a decimal, you would divide the given percentage by 100.   you can also accomplish the conversion by moving the decimal point over two places to the left.   for example, the decimal value of 80% is 80/100, or 0.8.   in order to convert a fraction to a decimal, you need to divide the numerator by the denominator.   for example, 3/4 is 0.75.   so, for choice (b) 0.5 3/4 (0.75), 80% (0.8) is the only choice in which the numbers are in order from least to greatest.  

correct answer:

b.(19,-2)