The 40 yards sprint times for a soccer team are found to be normally distributed with a mean of 5.2 seconds and a standard deviation of 0.3 seconds. What is the z-score for a player who runs a time of 5.6 seconds

0.67

Step-by-step explanation:

z = (x-μ)/σ, where

x is the raw score = 5.6 seconds

μ is the population mean = 5.2 seconds

σ is the population standard deviation = 0.3 seconds

z = 5.6 - 5.2/0.3

z = 0.66667

z score is approximately 0.67

The z-score for a player who runs a time of 5.6 seconds is 0.67

no i do not : ( what is it?