Jo is thinking of a positive integer less than 100. It is one less than a multiple of 8, and it is three less than a multiple of 7. What is the greatest possible integer Jo could be thinking of

n=25

Step-by-step explanation:

Let n be the greatest possible integer Jo could be thinking of. We know n<100 and n=8k-1=7l-3 for some positive integers k and l. From this, we see that 7l=8k+2=2(4k+1), so $7l$ is a multiple of 14. List some multiples of 14, in decreasing order: 112, 98, 84, 70, .... Since n<100, 112 is too large, but 98 works: . Thus,.

Hope this helped! :)

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.