Jose, who is making a fruit sale friends, using 7 oranges, 14 pears, 14 apples, 98 grapes, and
28 cherries. An average portion of fruit salad contains 7 grapes.
15. How many pears are in an average portion?
16. How many oranges are in an average portion?
17. How many cherries are in an average portion?

So I found this online:

Step-by-step explanation:

B + R + G + C = 280 ("The fruit salad has a total of 280 pieces of fruit.")

R = 2B ("There are twice as many raspberries as blueberries.")

G = 3C ("Three times as many grapes as cherries.")

C = 4R ("Four times as many cherries as raspberries.")

Now you can start substituting to get at the number of cherries there are, but first you need to do a little manipulation of these equations to get everything else in terms of the number of cherries. That third one, with grapes, is how you want it - solving for something else in terms of the number of cherries. So let's start with the last one, and divide both sides by 4.

C /4 = 4R /4

C /4 = 4R /4

C/4 = R    OR

R = C/4

Now let's work on the second one, with raspberries and blueberries. Since neither deal with cherries, you want to replace the number of either raspberries or blueberries with the number of cherries first. Since we just solved for R (above, R = C/4), we'll start with that replacement.

R = 2B

C/4 = 2B

Now we'll divide both sides by 2 to get B in terms of the number of cherries.

C/4 (/2) = 2B /2

C/8 = 2B/2

C/8 = B     OR

B = C/8

So now you've got every other letter in terms of C. We have R = C/4, B = C/8, and without changing that third equation, we have G = 3C. Now you go back to that first equation and put all three of these in, and you'll end up with just one variable (C).

B + R + G + C = 280

C/8 + C/4 + 3C + C = 280

Now you can simplify a bit by first combining all the Cs together.

C/8 + C/4 + 3C + C = 280

C/8 + (2)C/(2)4 + 3C + C = 280

C/8 + 2C/8 + 4C = 280

3C/8 + 4(8)C(/8) = 280 (Here it can be helpful to think of C as 8C/8 to help you combine the fraction into the whole number.)

3C/8 + 32C/8 = 280

35C/8 = 280

Now you just multiply both sides by 8 and then divide them by 35 to get rid of that fraction, and you get:

35C/8 = 280

35C/8 (*8) = 280 (*8)

35C/8 (*8) = 2240

35C = 2240

35C (/35) = 2240 (/35)

35C (/35) = 64

C = 64

So your answer is 64 cherries.

If you want to double-check this, you can do it this way:

It says there are 4 times as many cherries as raspberries. 64 is 4 times as many as 16, so there are 16 raspberries. It says there are 3 times as many grapes as cherries, and 3 times 64 is 192, so there are 192 grapes. Finally, it says there are twice as many raspberries as blueberries, and 16 is twice as many as 8, so there are 8 blueberries. If you add up 64 cherries plus 16 raspberries plus 192 grapes plus 8 blueberries, you get 280 total pieces of fruit, which is how many it says there are.

answer:

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204