In a fish tank there are 10 clown fish, 4 angel fish, 6 puffer fish, and 5 eels. What is the probability of scooping out a clown fish on the second scoop after scooping out a clown fish on the first scoop and not replacing it

3/8

Step-by-step explanation:

Given that

Number of clown fish = 10

Number of Angel fish = 4

Number of Puffer fish = 6

Number of Eels = 5

From the above, there exists 10 + 4 + 6 + 5 number of fishes

There exists 25 number of fishes.

Probability of picking a clown fish then is

C = 10 / 25

If the clown fish picked isn't replaced, then there exists 9 clown fishes, and 24 total fishes. This, the probability of picking another clown fish is

C = 9 / 24

C = 3 / 8

Thus, the answer is 3/8

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent