write the equation of the line that passes through the point (6,2) and is perpendicular to a line that passes through the points (-5,3) and (-1,-9

                y - 2 = ¹/₃(x - 6)      ← the point-slope form of the equation

                y = ¹/₃x                   ← the slope-intercept form of the equation

                x - 3y = 0               ← standard form of the equation

Step-by-step explanation:

The slope of line that passes through (-5, 3) and (-1, -9):

The slope of a line perpendicular to the line with the slope m₀:

The point-slope form of the equation of a line: y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.

(6, 2)    ⇒    x₁ = 6,  y₁ = 2

So:

    y - 2 = ¹/₃(x - 6)      ← the point-slope form of the equation

y - 2 = ¹/₃x - 2               {add 2 to both sides}

y = ¹/₃x                   ← the slope-intercept form of the equation

y - ¹/₃x = 0             {multiply both sides by (-3)}

x - 3y = 0               ← standard form of the equation

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

answer: the is put the 450

step-by-step explanation: