The function y=f(x)y=f(x) is graphed below. Plot a line segment connecting the points on ff where x=-5x=−5 and x=1.x=1. Use the line segment to determine the average rate of change of the function f(x)f(x) on the interval -5\le x \le 1−5≤x≤1?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

the correct answer is c

there are no choices to this, can you give us some choices so that i can answer it

step-by-step explanation: