Consider the line y = - 4x +3, Find the equation of the line that is parallel to this line and passes through the point (2, -3).

Step-by-step explanation:

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = - 4x + 3    ⇒   m₁ = -4    ⇒    m₂ = -4

The point-slope form of the equation of a line it's y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passing through.

m = -4

(2, -3)   ⇒   x₁ = 2,  y₁ = -3

point-slope form:

y - (-3) = -4(x - 2)

y + 3 = -4x + 8             {subtact 3 from both sides}

y = -4x + 5        ←    slope-intercept form