Mindy and troy combined ate 999 pieces of the wedding cake. mindy ate 333 pieces of cake and troy had \dfrac14
4

1
start fraction, 1, divided by, 4, end fraction of the total cake.
write an equation to determine how many pieces of cake (c)(c)left parenthesis, c, right parenthesis there were in total.

Equation: 3 + 1/4c = 9

Total pieces: 24

Step-by-step explanation:

I just took the test...

Sorry for not copying the explanation but you know how khan academy is...

whatever if you understand khan academy's language, here it is

Let ccc be the total number of pieces of wedding cake.

Hint #22 / 5

Mindy had 333 pieces of cake. Troy ate \dfrac14

4

1

 start fraction, 1, divided by, 4, end fraction of the cake, which is equal to \dfrac14c

4

1

 cstart fraction, 1, divided by, 4, end fraction, c.

Mindy and Troy combined to eat 3+\dfrac14c3+

4

1

 c3, plus, start fraction, 1, divided by, 4, end fraction, c pieces of cake.

Hint #33 / 5

Since they ate 999 pieces of cake, let's set this equal to 999:

\qquad 3+\dfrac14c=93+

4

1

 c=9space, 3, plus, start fraction, 1, divided by, 4, end fraction, c, equals, 9

Now, let's solve the equation to find the total number of pieces of wedding cake (c)(c)left parenthesis, c, right parenthesis.

Hint #44 / 5

\begin{aligned} \qquad 3+\dfrac14c&=9\\ \\ 3+\dfrac14c\pink{-3}&=9\pink{-3}&&\pink{\text{subtract }3} \text{ from each side}\\ \\ \dfrac14c&=6\\ \\ \dfrac{\dfrac14c}{\blue{\dfrac14}}&=\dfrac{6}{\blue{\dfrac14}}&&\text{divide each side by $\blue{\dfrac14}$}\\ \\ c&=24\end{aligned}

3+

4

1

 c

3+

4

1

 c−3

4

1

 c

4

1

4

1

 c

c

=9

=9−3

=6

=

4

1

6

=24

subtract 3 from each side

divide each side by  

4

1

Hope it helped lol

i think it might be a but you might want a second opinion