The figure below shows a square ABCD and an equilateral triangle DPC:
D
Ted makes the chart s...
Mathematics, 21.01.2021 01:20 hmae2304
The figure below shows a square ABCD and an equilateral triangle DPC:
D
Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:
Statements
In triangles APD and BPC; DP = PC
In triangles APD and BPC; AD = BC
Justifications
Sides of equilateral triangle DPC are equal
Sides of square ABCD are equal
Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 30°
Triangles APD and BPC are congruent SAS postulate
Which of the following completes Ted's proof? (1 point)
O In square ABCD; angle ADC= angle BCD
O In square ABCD; angle ADP= angle BCP
O In triangles APD and BPC; angle ADC
angle BCD
O In triangles APD and BPC; angle ADP = angle BCP
Answers: 1
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Ill mark the brainliest if you me with the these three questions 7,8,9
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1. find the area of the unshaded square 2. find the area of the large square 3. what is the area of the frame represented by the shaded region show
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