Factoring quadratics. Not in a rush, but I would appreciate some help on this. It's too late into the day to ask for help from my teacher. Explain how you did it step by step in the answer. There are more bots now, so please try to be helpful for once..

Step-by-step explanation:

Factor the expression:

(y+10)(2y+1)

Step-by-step explanation:

2y^2 +21y+10

Factor the expression by grouping. First, the expression needs to be rewritten as 2y^2 +ay+by+10. To find a and b, set up a system to be solved.

a+b=21

ab=2×10=20

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 20.

1,20

2,10

4,5

Calculate the sum for each pair.

1+20=21

2+10=12

4+5=9

The solution is the pair that gives sum 21.

a=1

b=20

Rewrite 2y^2 +21y+10 as (2y^2 +y)+(20y+10).

(2y ^2 +y)+(20y+10)

actor out y in the first and 10 in the second group.

y(2y+1)+10(2y+1)

Factor out common term 2y+1 by using distributive property.

(2y+1)(y+10)

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

ver más en -

step-by-step explanation: