I have two equations

a-2b=8 and 4a+3b=21 how can you solve one of these for a

Step-by-step explanation:

You could find a number that can be multiplied by 2 and a number for a that when you subtract from the number that you multiplied by 2 can give the result of 8.

Example:

a-2b=8: a=12-2•2=8

12-4=8

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6