Hey, here are all the problems. Im not sure how to do this and my teacher isnt giving me much time. Help would be apricated (9x + 5) - (-8x - 11)
(-5x - 7) + (-2x + 6)
(-x - 9) - (5x + 4)
(3x - 4) - (x - 7)
(7x + 4) - (5x + 5)
(2x - 3) + (7x + 11)
(-4x - 5) + 2(3x - 4)
2(6x - 7) - (2x + 3)
(5x + 4) - (5x + 12)

Step-by-step explanation:

9x+8x+5+11=  17x+16

-5x-2x-7+6=   -7x-1

-x-5x-9-4=   -6x-13

3x-x-4+7=    2x+3

7x-5x+4-5=  2x-1

2x+7x-3+11=  9x+8

-4x+6x-5-8=  2x-13

12x-2x-14-3=  10x-17

5x-5x+4-12=  -8

Hope this helps (brainliest is appriciated)

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!