These are isosceles equatorial triangle questions

Step-by-step explanation:

1) ABCD rectangle

In Δ ABE

∠BAE +  ∠B + ∠AEB = 180 {angle sum property}

   39 + 90 + ∠AEB = 180

             129 + ∠AEB = 180

                       ∠AEB = 180 - 129

                      ∠AEB = 51

∠AEB + ∠AED + ∠CED = 180      {Straight line angles}

            51 + x + 66 = 180

              117 + x  = 180

                      x = 180 - 117

                    x = 63

2) XYZ  equilateral triangle

In equilateral triangle each angle = 60°

∠XZY = 60

∠XZY + ∠XZW = 180            {linear pair}

 60+ ∠XZW = 180

            ∠XZW = 180 - 60

∠XZW = 120

In ΔXZW,

120 + 35 +x = 180  {angle sum property of triangle}

        155 +x = 180

                 x = 180 - 155

                x = 25

PQR isosceles triangle

PQ = PR

∠PRQ = ∠Q =  69°

∠PRS + ∠PRQ = 180   {linear pair}

 ∠PRS + 69 = 180

        ∠PRS = 180 - 69

        ∠PRS = 111

In ΔPRS

x + 111 + 31 = 180         {Angle sum  property of triangle}

         x + 142 = 180

                x = 180 - 142

              x = 38

8y^50

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068