Find the end behavior of f(x)= 5x^3-90x Find the x- intercepts of f(x)

Equation is f(x)=5x^3-90x

Its x-intercepts will be at 0, 9 and -9.

For the end behavior, because it's cubic and subtracts a multiple of x¹, this curve will primarily have a positive slope, but briefly a negative one when x is very near zero.

Step-by-step explanation:

We can factor this fairly easily, as both terms are divisible by 5x. After factoring those out they become a difference of squares, giving us all three factors of the function:

With that we can say that its x-intercepts will be at 0, 9 and -9.

Being a cubic function with a positive coefficient on the first term, we know that this curve will primarily have a positive slope, but briefly a negative one when x is very near zero.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

include a picture of the drawing in order for me to

step-by-step explanation: