Pls help i dont need working out just answers

A) y = -(8/3)m - 2

B) y = 4x - 1

C) y = -3.2x - 4

D) y = -2.5x - 3

Step-by-step explanation:

A) In the first equation, when x = 0, y = -2

From y = mx + c, we can say that

-2 = 0 + c

c = -2

Also,when y = 0, x = -0.75

Thus, 0 = -0.75m - 2

m = -2/0.75 = -8/3

Thus, y = -(8/3)m - 2

B) when x = 0, y = -1

From y = mx + c, we can say that

-1 = 0 + c

c = -1

Also,when y = 0, x = 0.5

Thus, 0 = 0.5m - 2

m = 2/0.5 = 4

y = 4x - 1

C)when x = 0, y = -4

From -4 = mx + c, we can say that

-4 = 0 + c

c = -4

Also,when y = 0, x = -1.25

Thus, 0 = -1.25m - 4

m = - 4/1.25 = -3.2

y = -3.2x - 4

D) when x = 0, y = -3

From y = mx + c, we can say that

-3 = 0 + c

c = -3

Also,when y = 0, x = -1.2

Thus, 0 = -1.2m - 3

m = -3/1.2 = -2.5

y = -2.5x - 3

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation:

answer: the first graph

step-by-step explanation: