Examine rectangle JKLM, shown below. If JN = x + 3 and JL = 3x + 1, determine which of the following values is correct

NM = 8

Step-by-step explanation:

Given rectangle JKLM

JN = x + 3 and JL = 3x + 1

JN = 1/2JL as diagonals bisect each other and N is the midpoint of JL.

Substitute and solve for x:

x + 3 = 1/2(3x + 1)

2x + 6 = 3x + 1

3x - 2x = 6 - 1

x = 5

Find JN

JN = 5 + 3 = 8

Looking at the options, we see that

NM = JN = 8

Correct option is A

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: