What is an equation in point slope form of a line that passes through (-3,1) and has a slope of 2

y=2x+7

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 2. So you can right away fill in the equation for a line somewhat to read:

y=2x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-3,1). When x of the line is -3, y of the line must be 1.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-3,1).

So, why not plug in for x the number -3 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-3,1). y=mx+b or 1=2 × -3+b, or solving for b: b=1-(2)(-3). b=7.

answer: asdfghjkl,mnbv

step-by-step explanation:

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²