Gretta has 40 raffle tickets to sell. she is required to sell at least 15 tickets. she sells the raffle tickets for $10 each.
the amount of money gretta makes from selling x raffle tickets is represented by a function.
f(x)=10x
what is the practical range of the function?
a. all integers from 15 to 40, inclusive.
b. all multiples of 10 between 0 and 400, inclusive.
c. all real numbers.
d. all multiples of 10 between 150 and 400, inclusive.

(D) All multiples of 10 between 150 and 400, inclusive. i took the test myself.

Option d is correct that is range of the function is all multiples of 10 between 150 and 400, inclusive.

Step-by-step explanation:

We have been given the information that gretta is selling x raffle ticket by a function

f(x)=10 x

Range is the values that y takes in a particular function

Here, we will get any value which is multiple of 10 since we have a function 10 times of something whatever value we put for x we will get multiple of 10.

Hence, Option d is correct that is range of the function is all multiples of 10 between 150 and 400, inclusive.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.