If x⊥a and x⊥b, then

a || b.

a⊥y.

x || y.

z⊥a.

The correct option is 1.

Step-by-step explanation:

Given information: X⊥A and X⊥B.

It means X is perpendicular to A and X is perpendicular to B.

If two lines are perpendicular to a same line,  then both lines are parallel to each other.

Let we have three line l,m and n. If  l ⊥ m and l⊥n, then m║n.

Here X⊥A and X⊥B. So, A║B.

Therefore, the correct option is 1.

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.