How do you represent parts of a hyperbola algebraically?

The center is at the point (h, v).

The graph on both sides gets closer and closer to two diagonal lines known as asymptotes. The equation of the hyperbola, regardless of whether it’s horizontal or vertical, gives you two values: a and b. These help you draw a box, and when you draw the diagonals of this box, you find the asymptotes.

There are two axes of symmetry:

The one passing through the vertices is called the transverse axis. The distance from the center along the transverse axis to the vertex is represented by a.

The one perpendicular to the transverse axis through the center is called the conjugate axis. The distance along the conjugate axis from the center to the edge of the box that determines the asymptotes is represented by b.

a and b have no relationship; a can be less than, greater than, or equal to b.

You can find the foci by using the equation f 2 = a2 + b2.

hope this helps! may i pls have brainliest?

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.