Part F The club will base its decision about whether to increase the budget for the indoor rock climbing facility on the
analysis of its usage. The decision to increase the budget will depend on whether members are using the indoor
facility at least two times a week. Use the best measure of center for both of the original data sets to determine
whether the club should increase the budget. Assume there are four weeks in a month. If you think the data is
inconclusive, explain why.

Step-by-step explanation:

They should in crease the buget:

divide each number by 2 to see how often they go equally/use the data table you have available of the two climbers.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation: