Three siblings are participating in a family-friendly running event. - The oldest sibling begins at the start line of the race and runs 7 miles per hour the entire time. - The middle sibling begins at the start line and walks at 3.5 miles per hour throughout the race. - The youngest sibling joins the race 4 miles from the start line and runs 5 miles per hour the rest of the way.

The siblings walking or running at a constant rate, illustrates a linear function.

The complete question requires that, we match each graph to the sibling (see attachment)

Oldest sibling

--- start line

So, the equation is:

When

This means that;

The graph of the oldest sibling passes through

The graph of the oldest sibling is Graph B

Middle sibling

--- start line

So, the equation is:

When

This means that;

The graph of the middle sibling passes through

The graph of the middle sibling is Graph C

So, we can conclude that:

The graph of the youngest sibling is Graph A

Read more about graphs at:

link

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

idk

step-by-step explanation: i just don't