What is the standard form of the equation y+6=2(x-3)

Step-by-step explanation:

i found this on a website

where A is a positive integer and B, C are integers.

Rearrange

y−6=−3(x+2)

into this form distribute and simplify.

⇒y−6=−3x−6

add 3x to both sides.

3x+y−6=−3x+3x−6⇒3x+y−6=−6

add 6 to both sides.

3x+y−6+6=−6+6⇒3x+y=0←

in standard form

im very sorry if this is wrong D:

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

its c or d   take a lucky guess my dude