Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. If y varies directly as x, and y = 2 when x = 3, find y when x = 1.
a. y = 2x; y(1) = 2
c. 4
y - 3*; y(1) -
3
3
d.
y = -2
3
b.
yo 2 *;2(1) -
»-< x; 9(1) -
2
2.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

what shape is

2 equivalent expressions to represent the area of a rectangle and the top is n-3 and the side is 2

area of the rectangle = length * width

given length = n - 3

width = 2

replace it in the area

so area of the rectangle = (n-3) *2

= 2(n-3)

one of the expression is 2(n-3)

to get another expression we distribute 2 inside the parenthesis

2(n-3) is 2n - 6

so another expression is 2n - 6

two equivalent expression are

2(n - 3)   , 2n - 6