What is the area of the triangle in the diagram? O A 1/(5 - 4,) (52-32) O B. by, (12 - 11) oc / (I2 - I₃) 1 D. 2/1 = – v?) ( = 7 - 77)

What is the area of the triangle in the diagram? O A 1/(5 - 4,) (52-32) O B. by, (12 - 11) oc / (I2 - I₃) 1 D. 2/1 = – v?) ( = 7 - 77)

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."