Can someone please help me??

b=3, y=6

Step-by-step explanation:

Label the 2 equations:

2b +6y= 42 (1)

2b +4y= 30 (2)

(1) -(2):

(2b +6y) -(2b +4y)= 42 -30

2b +6y -2b -4y= 12

2y= 12

y= 12 ÷2 (÷2 on both sides)

y= 6

Susbt. y=6 into (2):

2b +4(6)= 30

2b +24=30

2b= 30 -24 (-24 on both sides)

2b= 6

b= 6 ÷2

b= 3

y = 6, b = 3

Step-by-step explanation:

Since both equations have 2b in them, subtracting them gets you a quick result because the 2b-2b cancels out!

2b + 6y = 42

2b + 4y = 30

-

       2y = 12

         y = 6

Then 2b = 42 - 36 = 6, so b = 6/2 = 3

the answer is 15 to your question