(04.02 MC) Write the equation of a line in standard form that has x-intercept (−P, 0) and y-intercept (0, −R).

Px − Ry = −PR

Px − Ry = PR

Rx + Py = −PR

Rx + Py = PR

The equation in standard form is:

Rx+Py = -PR

Step-by-step explanation:

The slope-intercept form of the line equation

where

Given

The y-intercept (0, -R)

The x-intercept (−P, 0)

Finding the slope between (0, -R) and  (−P, 0)

Thus, the slope between (0, -R) and  (−P, 0) is:

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We are given the y-intercept point (0, −R).

Thus, y-intercept b = -R

so substituting b = -R and in the slope-intercept form to determine the line of the equation

So, the slope-intercept form of the line equation is:

Converting the slope-intercept form of the line equation into standard form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

As

so converting into standard form

Multiply the equation by P

Py = -Rx - PR

Add -Rx to both sides

Rx+Py = -Rx - PR + -Rx

Rx+Py = -PR

Therefore, the equation in standard form is:

Rx+Py = -PR

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )