The longest length side of an acute isosceles triangles is 12 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides

8.5

Step-by-step explanation:

Given that;

The longest side of an acute isosceles triangle = 12 centimeters

Since the two remaining sides are congruent, then they both have the same length ;

Let the length of the two remaining sides = 2x,

The length of each side :

Length of longest side / sqrt(2)

x = 12 /sqrt(2)

x = 12 / 1.4142135

x =8.4852813

x = 8.5

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

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