A code consists of eight letters chosen from the 26 letters of the alphabet. What is the chance that any two of the letters are the same?

1/26 or 0.039 (approximate to 3 decimal places)

Step-by-step explanation:

A code consists of 8 letters of the English alphabet (which comprises a total of 26 distinct letters). What is the chance or probability that any 2 letters of/in the code are the same?

An example of such code with a repeated letter is GREENMAN.

This word (code) has 2 letters that are the same and that's letter 'E'.

The probability that a letter in the code in question will appear twice depends on the frequency of appearance of that letter in the English alphabet set.

Now, no letter in the English alphabet set appears twice! Because of this, every letter in the English alphabet has an equal probability of being picked to form a code or word.

Hence, the chance that any letter from the alphabet will be repeated once in this code (same as saying the chance that any two letters of the code are the same) is 1/26 and that's equal to 0.03846 ≅ 0.039

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %