Given \qquad \overline{BA}\perp\overline{BD}

BA

⊥

BD

start overline, B, A, end overline, \perp, start overline, B, D, end overline

\qquad m \angle CBD = 4x + 52^\circm∠CBD=4x+52

∘

m, angle, C, B, D, equals, 4, x, plus, 52, degrees

\qquad m \angle ABC = 8x - 10^\circm∠ABC=8x−10

∘

m, angle, A, B, C, equals, 8, x, minus, 10, degrees

Find m\angle CBDm∠CBDm, angle, C, B, D:

7,24

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

step-by-step explanation:

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group