Find the perimeter and area of a rectangle with length (6) and width (x + 2).

The perimeter of a rectangle is: P = 2x+16

The area of a rectangle is: A = 6x+12.

Step-by-step explanation:

Given

The length of a rectangle = l = 6

The width of a rectangle = w = (x+2)

To determine

The perimeter of a rectangle = P

The area of a rectangle = A

Determining the Perimeter of a rectangle

The perimeter of a rectangle can be determined using the formula

P = 2(l+w)

substitute l = 6 and w = (x+2)

P = 2(6+x+2)

P = 2(8+x)

P = 2x+16

Therefore, the perimeter of a rectangle is: P = 2x+16

Determining the Area of a rectangle

The Area of a rectangle can be determined using the formula

A = lw

substitute l = 6 and w = (x+2)

A = (6)(x+2)

A = 6x+12

Therefore, the area of a rectangle is: A = 6x+12.

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