The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs. Solve

Please help !

In bold below.

Step-by-step explanation:

let the shorter leg be x units long, then:

longer leg = x+4

and hypotenuse = x + x + 4 - 8 = 2x - 4 units.

By Pythagoras:

(2x - 4)^2 = x^2 + (x + 4)^2

4x^2 - 16x + 16 = x^2 + x^2 +8x + 16

2x^2 - 24x = 0

2x(x - 12) = 0

x = 12.

So the shorter leg = 12 units

Longer leg = 4 + 12 = 16 units and

Hypotenuse =  12 + 16 - 8 = 20 units.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

function 2 has a greater rate of change than function 1

function 2 has a greater y-intercept than function 1

step-by-step explanation: