Help me plsss fast due at 7

2y+7x

5y−7x

=−5

=12

We notice that the first equation has a 7x7x7, x term and the second equation has a -7x−7xminus, 7, x term. These terms will cancel if we add the equations together—that is, we'll eliminate the xxx terms:

\begin{aligned} 2y+\redD{7x} &= -5 \\ +~5y\redD{-7x}&=12\\ \hline\\ 7y+0 &=7 \end{aligned}

2y+7x

+ 5y−7x

7y+0

=−5

=12

=7

Solving for yyy, we get:

\begin{aligned} 7y+0 &=7 7y &=7 y &=\goldD{1} \end{aligned}

7y+0

7y

y

=7

=7

=1

Plugging this value back into our first equation, we solve for the other variable:

\begin{aligned} 2y+7x &= -5 2\cdot \goldD{1}+7x &= -5 2+7x&=-5 7x&=-7 x&=\blueD{-1} \end{aligned}

2y+7x

2⋅1+7x

2+7x

7x

x

=−5

=−5

=−5

=−7

=−1

The solution to the system is x=\blueD{-1}x=−1x, equals, start color #11accd, minus, 1, end color #11accd, y=\goldD{1}y=1y, equals, start color #e07d10, 1, end color #e07d10.

We can check our solution by plugging these values back into the original equations. Let's try the second equation:

\begin{aligned} 5y-7x &= 12 5\cdot\goldD{1}-7(\blueD{-1}) &\stackrel ?= 12 5+7 &= 12 \end{aligned}

5y−7x

5⋅1−7(−1)

5+7

=12

=

?

12

=12

Step-by-step explanation:

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

sorry, i can't understand your question. will later if you describe more clearly!

: )