Which equation contains the points (-1,-8) and (3,4)

y = 3x –5

Step-by-step explanation:

for slope-intercept form, y = mx + b

find the slope, m

(-8 -4)/(-1-3) = m

-12/-4 =m

3 = m

Substitute for m and use either coordinate for y and x to calculate b

4 = 3(3) + b

4 = 9 + b. Subtract 9 from both sides

4 –9 = b

–5 = b. Rewrite the equation with the calculated values for m and b

y = 3x –5

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is a if my teacher taught me correct