The sum of two numbers is 40.if the greater number is 8 more than the smaller one , find the numbers

16 and 24

Step-by-step explanation:

let the 2 numbers be x and y, x > y , then

x + y = 40 → (1)

x = y + 8 → (2) [ greater number 8 more than smaller ]

Substitute x = y + 8 into (1)

y + 8 + y = 40, that is

2y + 8 = 40 ( subtract 8 from both sides )

2y = 32 ( divide both sides by 2 )

y = 16

Substitute y = 16 into (2)

x = 16 + 8 = 24

The 2 numbers are 16 and 24

the correct answer is 5 6 and 7

45

step-by-step explanation: