The cost of a car rental is $25 per day plus 22 per mile. You are on a daily budget of $90. Write and solve an inequality to find the greatest distance you can drive each day while staying within your budget. Use pencil and paper. Find 2 other two-step inequalities with the same solutions.

You can drive, at most, 2.95 miles per day.

x ≤ 2.95

Step-by-step explanation:

In a single day, you can spend at most $90

Then if C represents the cost of renting the car, then we will have the inequality:

C ≤ $90

Now let's find the equation for C.

We know that we have a fixed cost of $25 plus $22 per mile, then if you drive x miles, the total cost will be $25 plus x times $22, or:

C = $25 + x*$22.

We can now replace that in the inequality:

$25 + x*$22 ≤ $90

Now let's isolate the variable x

x*$22 ≤ $90 - $25

x*$22 ≤ $65

x ≤ $65/$22 = 2.95

x ≤ 2.95

You can drive at most, 2.95 miles per day.

To find other inequalities with the same solution we can start with the solution:

x ≤ 2.95

Now let's multiply both sides by a number (the units of the number can be dollars, in that way we can make a similar problem)

Let's multiply both sides by $10:

x*$10 ≤ 2.95*$10 = $29.5

x*$10 ≤ $29.5

Now let's add the same number in both sides, for example, $5.

x*$10 + $5 ≤ $29.5 + $5 = $34.5

x*$10 + $5 ≤ $34.5

We could write this problem as:

"To rent a cab in your city, you have an initial cost of $5, plus $10 for each mile driven. How many miles could you drive if at most you can spend $34.50?"

You could be more creative with the problem, but this is the way in which you can craft problems of this type when you already know the solution.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.