The rope that can fence out the square garden of length 250m can fence another circular garden twice. What is the area and perimeter of the circular garden? (Wrong answers will be reported)

Perimeter of circular garden=500m

Area=19,894 sq m

Step-by-step explanation:

250x4=1000

1000/2=500m circle perimeter

Pi x Dia=Circumference

3.14159 x Dia=500m

Dia=159.16m

Rad=159.16/2=79.58m

Area=Pi x Rad^2=2.14159 x 79.58^2=19,894 m^2

The circumference of the circular garden is 500 meters.

The area is approximately 19891 square meters.

If you use a Rounded value of 80m for the radius, the Area works out to about 20106 square meters.

Step-by-step explanation:

The total length of the rope is 1000m. 4×250=1000

That is enough to fence the circular garden twice, so the "perimeter" of that garden-- the circumference-- is 500m

To find the area, first find the diameter:

500÷π = 159.15

Area of a circle is A=πr²

The radius is half the diameter.

79.57 so r² is about 6331.4

Multiply by π to get the area:

about 19890.6 m²

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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