What’s the sum(2r-6)+4(r-3

=6r−18

Step-by-step explanation:

Distribute:

=2r+−6+(4)(r)+(4)(−3)

=2r+−6+4r+−12

Combine Like Terms:

=2r+−6+4r+−12

=(2r+4r)+(−6+−12)

=6r+−18

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."