The points (6, g) and (5, 5) fall on a line with a slope of 3. What is the value of g?

g=8

Step-by-step explanation:

First, let's find the equation of the line.

Using point-slope form, which is y-y1=m(x-x1)

we can substitute the given slope (3) and the point (5,5) into the equation

y-5=3(x-5)

do distributive property

y-5=3x-15

add 5 to both sides

y=3x-10

the equation of the line is y=3x-10

since the point (6,g) will fall on the line, we can put it into the equation to find y

y=3(6)-10

y=18-10

y=8

y, or g=8

hope this helps!

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)