What is the difference x/x^2+3+2 - 1/(x+2)(x+1)

#4,   x-1/(x^2+3x+2)

Step-by-step explanation:

x/(x^2+3x+2) - 1/((x+2)(x+1))

Convert the 1/((x+2)(x+1)) to 1/(x^2+3x+2)

now you have a common denominator to subtract

x/(x^2+3x+2) - 1/(x^2+3x+2)

results x-1/(x^2+3x+2)

the answer is 62

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse