Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid $1360, how many first class and tourist class passengers were there?

There were 40 tourist class passengers and 12 first class passengers.  

Explanation:

Let the number of passengers who booked for tourist class be

=

x

Then, number of passengers who booked for first class

=

52

−

x

According to question,

Total money paid = $25(tourist class)+$30(first class)  

$

1360

=

$

25

(

x

)

+

$

30

(

52

−

x

)

1360

=

25

x

+

1560

−

30

x

1360

−

1560

=

25

x

−

30

x

−

200

=

−

5

x

x

=

−

200

−

5

x

=

40

So, there were 40 tourist class passengers.

Now first class passengers

=

52

−

x

=

52

−

40

=

12

∴

There were 40 tourist class passengers and 12 first class passengers.  

As a check

Total money paid = $25(tourist class)+$30(first class)  

R

H

S

=

$

25

(

40

)

+

$

30

(

12

)

$

1000

+

$

360

=

$

1360

L

H

S

=

$

1360

Hence verified.

answer is x<

c > -10.55

step-by-step explanation: