How many solutions exist for the given equation? } (x + 12) = 4x – 1
zero
one
two
infinitely many

The given equation has one solution.

Step-by-step explanation:

Given equation is:

(x+12) = 4x-1

We will solve the equation to check how many solutions it has.

x+12 = 4x-1

Adding 1 on both sides

x+12+1 = 4x-1+1

x+13 = 4x

Subtracting x from both sides

x-x+13=4x-x

13 = 3x

x = 13/3

Hence,

The given equation has one solution.

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.