PLEASE HELP A cylinder has a 21.02 in. diameter. The linear speed of a point on the cylinder's surface is 18.12 ft/sec. What is the angular speed of the cylinder, in revolutions per hour?

11860.22 rev/hour

Step-by-step explanation:

The diameter if a cylinder, d = 21.02 inches

Radius, r = 10.51  inches

or

r = 0.875 feet

The linear speed of a point on the cylinder's surface is 18.12 ft/sec.

We need to find the angular speed of the cylinder.

The relation between the linear speed and the angular speed is given by :

Where

is angular speed

or

So, the required angular speed of the cylinder is 11860.22 rev/hour.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.