Three teams, A, B and C, play in a competition. games won by A: games won by B = 3:1
games won by B: games won by C = 5:1
Team B has won 10 games.
In total, how many games have the three teams won?

42 games

Step-by-step explanation:

From the ratio, we can deduce that;

For every 3 games A won, B won 1

Thus, if B won 10, then A has won 3(10) = 30

From the second part;

For every 1 game won by C, B won 5

since B won 10, then C won 10/5 = 2

So the total number of games won is;

A + B + C

= 2 + 30 + 10 = 42 games