The sum of three numbers is 41 The second number is 5 times the first
The third number is 14 less than the second
What is the third number?

11

Step-by-step explanation:

let the first number be n , then the second number is 5n and

the third number is 5n - 14

Sum the numbers and equate to 41

n + 5n + 5n - 14 = 41

11n - 14 = 41 ( add 14 to both sides )

11n = 55 ( divide both sides by 11 )

n = 5

Thus

first number = 5

second number = 5n = 5 × 5 = 25

third number = 5n - 14 = 5(5) - 14 = 25 - 14 = 11

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb