Juelle had $25,000 to invest. She invested part of that amount at 3% interest and part at 5% interest for one year. The amount of interest she earned for both investments was $1100. How much was invested at each rate?

The first amount invested at 3%= x = $7500

The second amount Invested at 5% = y = $17500

Step-by-step explanation:

Juelle had $25,000 to invest.

She invested part of that amount at 3% interest and part at 5% interest for one year.

The amount of interest she earned for both investments was $1100.

The formula for Simple Interest =

Principal × Rate × Time

Let us represent

The first amount invested at 3%= x

The second amount Invested at 5% = y

x + y= $25,000 Equation 1

x = 25,000 - y

3% × x + 5% × y = $1100 Equation 2

0.03x + 0.05y = 1100 Equation 2

We substitute 25000 - y for x in Equation 2

0.03x + 0.05y = 1100

0.03(25000 - y) + 0.05y = 1100

750 - 0.03y + 0.05y = 1100

Collect like terms

- 0.03y + 0.05y = 1100 - 750

0.02y = 350

y = 350/0.02

y = 17500

Solving for x

x = 25,000 - y

x = 25000 - 17500

x = 7500

Therefore:

The first amount invested at 3%= x = $7500

The second amount Invested at 5% = y = $17500

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

answer: i oofed

step-by-step explanation:

oofed=wow