Ten baseballs and four ping-pong balls cost $46. One baseball costs one dollar more than two ping-pong balls. Find the cost of one baseball and the cost of one ping-pong ball.

1 baseball cost $4

1 ping pong cost $1.5

Step-by-step explanation:

let the cost of baseball be b and the cost of ping pong be p

10 baseballs = 10b

4 ping pong = 4p

Adding both gives total $46

10b + 4p = 46 •••••••••(i)

baseball costs 1 dollar more than 2 ping pong

b = 2p + 1 •••••••(ii)

Substitute ii into i

10(2p + 1) + 4p = 46

20p + 10 + 4p = 46

24p = 46-10

24p = 36

p = 36/24

p = $1.5

b = 2p + 1

b = 2(1.5) + 1

b = 3 + 1 = $4

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2