What is the vertex of the graph of the quadratic function y = x^2 6x 10? (3, -1) (-3, -1) (-3, 1) (3, 1)

Y= x^2 + 6x + 10
y=(x+6/2)^2-6/2^2+10
y=(x+3)^2-3^2+10
y=(x+3)^2-9+10
y=(x+3)^2+1

This is what i found “answer: a rigid transformation preserves both the side lengths and the angle measures of a polygon. step-by-step explanation: rigid transformations are the transformations which does not affect the size and the shape of figure .” i hope this you for what your looking for. can you plz mark me brainliest?