What is the equation of the line perpendicular to 2x + y = -5 and passes through the point (4, -3)? Write your answer in slope-intercept form. Show all work.

2x+y= -5 is our equation and it passes through (4, -3)

point-slope formula= y-y1= m(x-x1)

fill in your formula, but flip the slope so its perpendicular. so slope is 1/2.

y+3=1/2(x-4) when i filled the formula in, i used 4 as x1 and -3 as y1.

y+3=1/2x-2 multiply x and -4 by 1/2

y=1/2x-5 subtract 3 from both sides.

Final y=1/2x-5

Also, i'm sorry my answer took so long the bell rang and so I had to leave this alone for a minute. Feel free to ask any questions :)